There are several factors that need to be known before a calculation can be used to decide the most suitable sized hydraulic gear motor for an application.
1) First of all find out if the required output torque from the hydraulic gear motor is starting torque or running torque. Not that either will effect the way you size the hydraulic gear motor, but it is worth remembering that starting torque is, in most instances, higher than running torque.
2) Required output speed from the hydraulic gear motor.
3) Available hydraulic oil pressure of the application hydraulic circuit.
4) Required output shaft, required mounting interface and required inlet and outlet porting, flanged or threaded.
5) Don’t forget the coupling from the hydraulic motor shaft to the driven shaft. jbj Techniques have a wide range of mechanical power transmission couplings to suit many applications. We would be happy to help.
Example calculation:
An application requires an output torque of 50 Nm at a speed of 2000 rpm and the hydraulic oil pressure available is 150 bar.
Using formula: Vm = (20 x pi x T) ÷ ΔP
Vm = Hydraulic gear motor displacement in cc/rev.
T = Required output torque 50Nm.
ΔP = 150 bar.
Put the above information into the formula:
Vm = (20 x 3.142 x 50) ÷ 150
Vm = 20.94 cc/rev.
The above figure gives you the theoretical required hydraulic motor displacement to meet the above requirements. However it does not take into account the hydraulic motors mechanical inefficiencies.
The nearest hydraulic motor to the above Vm displacement figure of 20.94 cc/rev would be the . . . read more
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